(x-3)^2/3-9(x-3)^1/3+20=0

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Solution for (x-3)^2/3-9(x-3)^1/3+20=0 equation: 


x in (-oo:+oo)

((x-3)^2)/3-((9*(x-3)^1)/3)+20 = 0

((x-3)^2)/3-3*(x-3)+20 = 0

((x-3)^2)/3+(-3*3*(x-3))/3+(3*20)/3 = 0

(x-3)^2-3*3*(x-3)+3*20 = 0

x^2-15*x+36+60 = 0

x^2-15*x+96 = 0

x^2-15*x+96 = 0

x^2-15*x+96 = 0

DELTA = (-15)^2-(1*4*96)

DELTA = -159

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

x belongs to the empty set

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